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VLD [36.1K]
2 years ago
11

There are 1200 students at Sophie’s school. One student’s name will be drawn at random to win a new bike. Hannah and Ethan are S

ophie’s best friends. What is the probability that
Sophie, Hannah, or Ethan will win the bike?

1. Describe the sample space for this problem.
2. Which outcome (or outcomes) of the sample space composes the event?
Mathematics
1 answer:
givi [52]2 years ago
3 0

Answer:

1/400

Step-by-step explanation:

3/1200 = 1/400

1) Sample space would consist of the 1200 names of the students

2) out of those 1200 outcomes, this event composes of three outcomes which are:

1) Sophie

2) Hannah

3) Ethan

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Which statement correctly identifies a local minimum of the graphed function?
Rina8888 [55]

Answer:

C. Over the interval [–1, 0.5], the local minimum is 1.

Step-by-step explanation:

From the graph we observe the following:

1) x intercepts are two points.

ii) y intercept = 1

f(x) = y increases from x=-infinity to -1.3

y decreases from x=-1.3 to 0

Again y increases from x=0 to end of graph.

Hence in the interval for x as (-1.3, 1) f(x) has a minimum value of (0,1)

i.e. there is a minimum value of 1 when x =0

Since [-1,0.5] interval contains the minimum value 1 we find that

Option C is right answer.

There is a local minimum of 1 in the interval [-1,0.5]



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3 years ago
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X = k x y
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3 years ago
Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir
kati45 [8]
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
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\\\\\\
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\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
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\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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Answer:

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\large\textit{Answer :}

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\tiny\textsc{HOPE HELPFUL ~}

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