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Lelechka [254]
3 years ago
6

Write a rule that represents the function (0,0)(1,0.5)(2,2)(3,4.5)(4,8)

Mathematics
1 answer:
kirza4 [7]3 years ago
6 0
The rule that represents those numbers is .....idk
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Fred's frog jumped 7 times as far as Al's frog. The 2 frogs jumped a total of 56 inches. How far did Fred's frog jump?
faust18 [17]
The answer is 7....................................
8 0
3 years ago
Read 2 more answers
Im too lazy to do this rn lol
gtnhenbr [62]

Answer:

You can drive at 53 miles per day.

Step-by-step explanation: Hope this helped )(-:

7 0
3 years ago
Let X ~ N(0, 1) and Y = eX. Y is called a log-normal random variable.
Cloud [144]

If F_Y(y) is the cumulative distribution function for Y, then

F_Y(y)=P(Y\le y)=P(e^X\le y)=P(X\le\ln y)=F_X(\ln y)

Then the probability density function for Y is f_Y(y)={F_Y}'(y):

f_Y(y)=\dfrac{\mathrm d}{\mathrm dy}F_X(\ln y)=\dfrac1yf_X(\ln y)=\begin{cases}\frac1{y\sqrt{2\pi}}e^{-\frac12(\ln y)^2}&\text{for }y>0\\0&\text{otherwise}\end{cases}

The nth moment of Y is

E[Y^n]=\displaystyle\int_{-\infty}^\infty y^nf_Y(y)\,\mathrm dy=\frac1{\sqrt{2\pi}}\int_0^\infty y^{n-1}e^{-\frac12(\ln y)^2}\,\mathrm dy

Let u=\ln y, so that \mathrm du=\frac{\mathrm dy}y and y^n=e^{nu}:

E[Y^n]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu}e^{-\frac12u^2}\,\mathrm du=\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu-\frac12u^2}\,\mathrm du

Complete the square in the exponent:

nu-\dfrac12u^2=-\dfrac12(u^2-2nu+n^2-n^2)=\dfrac12n^2-\dfrac12(u-n)^2

E[Y^n]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{\frac12(n^2-(u-n)^2)}\,\mathrm du=\frac{e^{\frac12n^2}}{\sqrt{2\pi}}\int_{-\infty}^\infty e^{-\frac12(u-n)^2}\,\mathrm du

But \frac1{\sqrt{2\pi}}e^{-\frac12(u-n)^2} is exactly the PDF of a normal distribution with mean n and variance 1; in other words, the 0th moment of a random variable U\sim N(n,1):

E[U^0]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{-\frac12(u-n)^2}\,\mathrm du=1

so we end up with

E[Y^n]=e^{\frac12n^2}

3 0
3 years ago
There are 340 freshman at BHSS. This is one hundred less than two times the number of sophomores. Find the number of sophomores
natta225 [31]
To put it into an equation, it would be:

340 = 2x - 100

with x being the amount of sophomores at BHSS.

Solve it:

340 + 100 = 2x

2x = 440

x = 220

The number of sophomores at BHSS is 220.




5 0
3 years ago
Use logarithms to find the exact solution for 7(17^−9)−7=49.
ch4aika [34]
ANSWER: x = -0.082


EXPLANATION:

1. Apply logarithm to both sides of the
equation. If one of the terms has base 10,
use common logarithm, otherwise, use
natural logarithm

2. Use the different properties of logarithms
to solve for the variable.

17
-92 _ 7 = 49
7.17-92 = 56
17-92 = 8
10g17(8)
-92
2
log, 7(8)
-9
log(8)
log(17)
-9
I=
-0.082
2 of 3
Add both sides by 7
Divide both sides by 7
Convert to logarithm
Divide both sides by - 9
6 0
2 years ago
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