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Lisa [10]
3 years ago
10

The value x = 7 is a solution to each of the following except what.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

Where are the answer choices??

Step-by-step explanation:

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You have a box with dimensions 2 ft. x 4 ft. x 3 ft. a. If you want to wrap the box, what is the minimum amount of wrapping pape
shusha [124]

Answer: A) 52 ft  B) $134.68

Step-by-step explanation:

First find the surface area by multiplying the dimensions together.

2 x 4 = 8

2 x 3 = 6

4 x 3 = 12

Then add them up and multiply by two because there are two of each side.

26 x 2 = 52

To find the cost, multiply 52 by $2.59 to get the price.

52 x $2.59 = $34.68

5 0
3 years ago
You purchased 150 feet of chain that normally sells for $0.15 per inch. You were charged $22.50 for the sale. Was the price corr
icang [17]
No it was not correct because if there is 12 inches in one foot and you divid 150 by 12 you get 12.6. Then you would multiply 12.6 and .15 and you would get 20.40. So you were charged extra with out tax.
8 0
4 years ago
The axis of symmetry of the graph of h is x = - 3. which ordered pair represents the additional point on the graph of h?​
Tresset [83]

Answer: (1,-5)

Step-by-step explanation:it’s the answer

4 0
3 years ago
What is the x-intercept of the line with the equation 4x + 3y = 12?
belka [17]

To find the x intercept replace y with 0 in the equation and solve for x:

4x +3(0) = 12

Simplify:

4x +0 = 12

4x =12

Divide both sides by 4:

x = 12/4

x = 3

The x intercept would be (3,0)

5 0
4 years ago
The distance d that a certain particle moves may be calculated from the expression d = at + bt2 where a and b are constants; and
pychu [463]
Guven that the <span>distance d that a certain particle moves may be calculated from the expression d = at + bt^2 where a and b are constants; and t is the elapsed time.

Distance is a length and hence the dimension of distance is L.

Now, at and bt^2 also will have the dimension of L.

</span><span>Time has a dimension of T.

For at, let the dimension of a be X, then
XT=L \\  \\ \Rightarrow X=\frac{L}{T}

For bt^2, let the dimension of b be Y, then
YT^2=L \\  \\ \Rightarrow Y= \frac{L}{T^2}

Therefore, the dimension of a is \frac{L}{T} while the dimension of b is \frac{L}{T^2}.
</span>
4 0
3 years ago
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