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3 years ago

5

Which of the following points would fall on the line produced by the point-slope form equation y - 8 = 4/5(x - 1) when graphed

1 answer:

HACTEHA [7]3 years ago

6 0

This says that x will equal -9

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Miguel biked 14 km in the same amount of time that linda hiked 10 km. Miguel's rate was 4 km/h more than linda's. How fast did e

matrenka [14]

The first thing we must do is define a variable.

We have then:

x: Linda's speed.

Then, by definition, the time traveled is equal to the distance between the velocity.

We have then:

For Linda:

$t = \frac{10}{x}$

For Miguel:

$t = \frac{14}{x + 4}$

Then, since time is the same, then:

$\frac{10}{x} = \frac{14}{x + 4}$

Clearing Linda's speed we have:

$10 (x + 4) = 14x$

$10x + 40 = 14x$

$40 = 14x-10x$

$40 = 4x$

$x = \frac{40}{4}$

$x = 10$

Then, Miguel's speed is:

$x + 4 = 10 + 4 = 14$

Answer:

Linda's speed is 10 Km/h

Miguel's speed is 14 Km/h

3 0

2 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

2 years ago

If correct Brainliest

ElenaW [278]

Answer:

a

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

There is 3 4 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1 4 of the pie that was left. Enter how much of the

lora16 [44]

Answer:

3/16

Step-by-step explanation:

Let the size of the whole apple be T

Given that 3/4 of the apple is left, it means the size left

= 3T/4

Since Victor plans to eat 1/4 of the pie that was left, this amounts to

1/4 * 3T/4

= 3T/16

This means that Victor will eat 3/16 of the whole pie tomorrow

5 0

2 years ago

Santa's Wonderland is an extravagant holiday light display that is open from early November through January each year. The entry

Fofino [41]

Ok,
f(0.35)= 7f/20

f(-5.2)=-26f/5

f(10)= 10f

f(-0.5)= -f/2

as for the last question I am not quite sure, sorry....hope I helped a little :)

5 0

3 years ago