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2 years ago

What is the midpoint of a segment with endpoints at(-4,-8) and (8, 10)?

Mathematics

1 answer:

vekshin12 years ago

4 0

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4,-8) and (8, 10)

The midpoint is

$M = ( \frac{ - 4 + 8}{2} , \: \frac{ - 8 + 10}{2} ) \\ = ( \frac{4}{2} , \frac{2}{2} )$

We have the final answer as

Hope this helps you

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The cost of downloading one song from a website is $0.99. which equation can be used to find t, the cost in dollars of downloadi

Alika [10]

Hello from MrBillDoesMath!

Answer:

Choice H: , t = 0.99n

Discussion:

Download costs:

1 song: 0.99

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Thank you,

MrB

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3 years ago

Read 2 more answers

Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu

Murljashka [212]

Answer:

The value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=30t-\frac{g_s}{2} t^2$

Velocity is defined as the rate of change of position. Therefore,

$v(t)=\frac{d}{dt}(s(t))$

So, the velocity function is

$v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st$

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

$v(t)=30-g_st=0\\\\g_s=\frac{30}{t}$