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andrew11 [14]
3 years ago
8

What is the solution to the linear equation?

Mathematics
2 answers:
Burka [1]3 years ago
8 0

p=1

To better understand the problem see the attached figure

we have

\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p

Multiply by 5 both sides

5(\frac{2}{5}+p)=5(\frac{4}{5}+\frac{3}{5}p)

2+5p=4+3p

Group terms that contain the same variable p and move the constant to the other side of the equation

5p-3p=4-2

2p=2

p=1

MrRissso [65]3 years ago
4 0

Answer:

p=1

Step-by-step explanation:

We are given that an equation

\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p

We have to find the solution of given linear equation .

Subtraction property of equality

p-\frac{3}{5}p+\frac{2}{5}=\frac{4}[5}

\frac{5p-3p}{5}+\frac{2}{5}=\frac{4}{5}

Combine like terms

\frac{2}{5}p+\frac{2}{5}=\frac{4}{5}

\frac{2}{5}p=\frac{4}{5}-\frac{2}{5}

Subtraction property of equality

\frac{2}{5}p=\frac{2}{5}

When a fraction term in multiply  goes  form one side to other side then the term will be reciprocal.

p=\frac{2}{5}\times \frac{5}{2}

p=1

Hence, p=1

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