Question

What is the solution to the linear equation?

Answer 1

$p=1$

To better understand the problem see the attached figure

we have

$\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p$

Multiply by $5$ both sides

$5(\frac{2}{5}+p)=5(\frac{4}{5}+\frac{3}{5}p)$

$2+5p=4+3p$

Group terms that contain the same variable p and move the constant to the other side of the equation

$5p-3p=4-2$

$2p=2$

$p=1$

Answer 2

Answer:

p=1

Step-by-step explanation:

We are given that an equation

$\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p$

We have to find the solution of given linear equation .

Subtraction property of equality

$p-\frac{3}{5}p+\frac{2}{5}=\frac{4}[5}$

$\frac{5p-3p}{5}+\frac{2}{5}=\frac{4}{5}$

Combine like terms

$\frac{2}{5}p+\frac{2}{5}=\frac{4}{5}$

$\frac{2}{5}p=\frac{4}{5}-\frac{2}{5}$

Subtraction property of equality

$\frac{2}{5}p=\frac{2}{5}$

When a fraction term in multiply  goes  form one side to other side then the term will be reciprocal.

$p=\frac{2}{5}\times \frac{5}{2}$

$p=1$

Hence, p=1