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3 years ago

Square root of 2025 by prime factorisation methodPlease explain step by step

Mathematics

1 answer:

Mice21 [21]3 years ago

4 0

Answer:

Step-by-step explanation:2025....use the smallest prime number to divide the number 2025 till you get to a point were it can't be divided again . Group each prime number with a partner of its value like this :

5×5×3×3×3×3........ then use bracket to separate them like this (5×5)(3×3)(3×3)........ then take a number from each 5×3×3 then multiply to get 45

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Need help!! please/Thank you

NARA [144]

Answer:

$50~in$

Step-by-step explanation:

$perimter=AB+AM+BM$

$AM=2EM=2(9in)=18in$

$BM=25E=2(7in)=14in$

∠m= $180-$ (∠A+∠B)= 180-(70+40)

∠m= 70⇒ AB= AM⇒AB=18

$perimeter=18+14+18=$

$50~in$

--------------------------

hope it helps...

have a great day!!

5 0

3 years ago

Read 2 more answers

Help its pi, ill give brainiest to the first answer show work please :)

saw5 [17]

Answer:

16m

50.24m

200.96m^2

Step-by-step explanation:

13. 8*2=16

14. 8m

15. 2pi r = 2* pi* 8= 50.24

16. pi r^2 = pi * 8^2= 200.96m^2

8 0

3 years ago

Read 2 more answers

What are the period and phase shift for f(x) = 3 tan(4x + π)?

Y_Kistochka [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now.. with that template above in mind, let's see yours

$\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

7 0

3 years ago

5) Find the area of a rectangle with points at (-8,5), (2,5), (2,-3) and (-8,-3).

Lady bird [3.3K]

Answer:

80 units²

Step-by-step explanation:

Given vertices of a rectangle:

A = (-8, 5)
B = (2, 5)
C = (2, -3)
D = (-8, -3)

As points A and D share the same x-coordinate, and points B and C share the same x-coordinate, the difference between the different x-coordinates is the length of the rectangle:

$\begin{aligned}\implies \textsf{Length} & = x_B-x_A\\& = 2-(-8)\\& = 2+8\\& = 10\; \sf units\end{aligned}$

As points A and B share the same y-coordinate, and points C and D share the same y-coordinate, the difference between the different y-coordinates is the width of the rectangle:

$\begin{aligned}\implies \textsf{Width} & = y_A-y_D\\& = 5-(-3)\\& = 5+3\\& = 8\; \sf units\end{aligned}$