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2 years ago

Was the expression a^2-b^2 = (a+b)(a-b) invented or discovered?

Mathematics

2 answers:

Andreyy892 years ago

6 0

Answer:

the expression is invented

Contact [7]2 years ago

3 0

I would say it was discovered.
Expanding (a + b)(a - b)
= a(a - b) + b(a - b)
= a^2 - ab + ba - b^2
= a^2 - b^2
So factorising the difference between two squares simply reverses the equation

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What is the missing exponent of 32=2?

MrRa [10]

32 = 2^5 <==== my answer is too short..lol

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3 years ago

Read 2 more answers

Solve equation <br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bk-4%7D%7B3%7D%20%3D%203" id="TexFormula1" title="\frac{k-4}{

3241004551 [841]

k-4/3= 3

Mutiply both sides by 3 .

(3)(k-4/3)= (3)(3)

Cross out 3 and 3 , divide by 3 and then becomes k-4= 9

Move -4 to the other side

Sign changes from -4 to +4

k-4+4= 9+4

k= 13

Answer: k= 13

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3 years ago

The graph below describes the journey of a train between two cities.

Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200 km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey = 62.5 km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time Velocity km/hr

0 Min ( 0 hr) 0

15 Min (1/4 hr) 50

45 Min (3/4 hr) 50

60 MIn ( 1 hr) 100

90 Min ( 3/2 hr) 100

120 Min ( 2hr) 0

Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)

= 200 km/h²

Hence, Answer for [A] = 200 km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

= 25/4 + 25 + 75/4 + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2 = 62.5 km/hr

[RevyBreeze]

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2 years ago

Use rounding to estimate the product. Is your estimate an underestimate or an overestimate? 8 × 9.82

kkurt [141]

Answer:

Over

Step-by-step explanation:

7 0

3 years ago

Given that (in picture)...

GuDViN [60]

<h3>Answer: a = -3 and b = 5</h3>

=================================================

Work Shown:

Multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\$

We end up with something in the form $a+b\sqrt{2}$ where a = -3 and b = 5

7 0

3 years ago