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3 years ago

Was the expression a^2-b^2 = (a+b)(a-b) invented or discovered?

Mathematics

2 answers:

Andreyy893 years ago

6 0

Answer:

the expression is invented

Contact [7]3 years ago

3 0

I would say it was discovered.
Expanding (a + b)(a - b)
= a(a - b) + b(a - b)
= a^2 - ab + ba - b^2
= a^2 - b^2
So factorising the difference between two squares simply reverses the equation

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Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number soluti

Margarita [4]

we know that

In a quadratic equation of the form $ax^{2}+bx+c=0$ the discriminant is equal to

$(b^{2} -4ac)$

if $(b^{2} -4ac)> 0$ -------> the equation has two real number solutions

if $(b^{2} -4ac)= 0$ -------> the equation has one real number solution

if $(b^{2} -4ac)< 0$ -------> the equation has two complex number solutions

In this problem we have

$-2x^{2} +3=0$

$a=-2\ b=0\ c=3$

substitute in the formula

$(0^{2} -4(-2)(3))=24$

$24 > 0$ ----> the equation has two real number solutions

therefore

<u>the answer is</u>

the equation has two real number solutions

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3 years ago

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Step-by-step explanation:

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Jet001 [13]

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ruslelena [56]

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