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Reil [10]
3 years ago
7

Select all possible values of x. x^7/3-5x^4/3 +6x^1/3= 0.

Mathematics
1 answer:
lord [1]3 years ago
4 0

Answer:

x=0, x=2, x=3

Step-by-step explanation:

I hope this helps.

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Under his cell phone plan, Nathan pays a flat cost of $36 per month and $3 per gigabyte. He wants to keep his bill under $45 per
victus00 [196]

Answer:

Is there a way you can add an image?

Step-by-step explanation:

3 0
3 years ago
A farm stand sold 12 ears of corn for $4. The farm stand sold 180 ears of corn at the same rate.
Scorpion4ik [409]
Divide 4 by 12, which equals approximately 0.33333, then multiply that to 180, which gives us 60. So she sold 180 ears of corn for $60.
5 0
3 years ago
Read 2 more answers
Please help!
Reika [66]

Answer:

(1,-5)

Step-by-step explanation:

The given system of inequalities are;

y\:

and

y\:

The point that is a solution will satisfy the two inequalities.

Checking for (1,-5)

-5\: and -5\:

-5\:: True -5\: : True

This point lies in the solution region.

Checking for (1,5)

5\: and 5\:

5\:: False 5\: : False

This point does not lie in the solution region.

Checking for (5,1)

1\: and 1\:

1\:: False 1\: : True

This point does not lie in the solution region.

Checking for (-1,5)

5\: and 5\:

5\:: True 5\: : False

This point does not lie in the solution region.

4 0
3 years ago
Read 2 more answers
Elijah gets paid $15.50 per hour in addition to a weekly salary of $50. This week he wants to earn more than $400. How many hour
8090 [49]
H=number of hours
m=total salary
m=15.50h+50
put 400 in for m
400=15.50h+50
now solve for h
400=15.50h+50
-50. -50
350=15.50h
Divide 350 by 15.50to get your final answer
you get a long decimal so I rounded it.
22.6 hours
4 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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