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Reil [10]
2 years ago
7

Select all possible values of x. x^7/3-5x^4/3 +6x^1/3= 0.

Mathematics
1 answer:
lord [1]2 years ago
4 0

Answer:

x=0, x=2, x=3

Step-by-step explanation:

I hope this helps.

You might be interested in
A, B, and C are points of tangency. CQ = 5, PQ = 10, and PR = 14. What is the perimeter
igomit [66]

*see attachment for diagram

Answer:

Perimeter = 38

Step-by-step explanation:

Recall: when two tangents are drawn to meet at a point outside a circle, the segments of the two tangents are congruent.

Given,

CQ = 5

PQ = 10

PR = 14

Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR

CQ = QB = 5 (tangents drawn from an external point)

BP = PQ - QB

BP = 10 - 5 = 5

BP = PA = 5 (tangents drawn from an external point)

AR = PR - PA

AR = 14 - 5 = 9

AR = RC = 9 (tangents drawn from an external point)

✔️Perimeter of ∆PQR = RC + CQ + QB + BP + PA + AR

= 9 + 5 + 5 + 5 + 5 + 9

Perimeter = 38

7 0
3 years ago
Please help it an emergency and I give Brainiest.
notsponge [240]
Look at where the lines intersect each other, if they do then you can use one of the coordinates. the lines that don’t touch means no solution
5 0
3 years ago
Read 2 more answers
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

sec(90\times2+0)= -sec0^\circ  = -1


F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of .6 minutes. What
Ivanshal [37]

Answer:

0.04746

Step-by-step explanation:

To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes.  Either use a table of z-scores or a calculator with probability distribution functions.

In this case I will use my old Texas Instruments TI-83 calculator.  I select the normalcdf( function and type in the following arguments:  :

normalcdf(-100, 5, 4, 0.6).  The result is 0.952.  This is the area under the curve to the left of x = 5.  But we are interested in finding the probability that a conversation lasts longer than 5 minutes.  To find this, subtract 0.952 from 1.000:   0.048.  This is the area under the curve to the RIGHT of x = 5.

This 0.048 is closest to the first answer choice:  0.04746.

8 0
2 years ago
Jean cost $45, they are now priced $40. find the percent of change from $45 to $40
Kisachek [45]
The percent of change is 9%
3 0
3 years ago
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