Answer:
could you provide a photo of sam's work? or show his work?
Step-by-step explanation:
Answer:
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
Step-by-step explanation:
Let the random variable Y have a geometric distribution g (y;p) = pq y-¹
The m.g.f of the geometric distribution is derived as below
By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)
= pe^t ∑(e^tq)^y-1
= pe^t/1- qe^t, where qe^t <1
In order to differentiate the m.g.f we write it as
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
M₀` (t) = pe^-t (e^-t -q) ^ -2 and
M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2
Hence
E (y) = p (1-q)-² = 1/p
E (y²) =2 p (1-q)-³ - p (1-q)-²
= 2/p² - 1/p and
σ² = [E (y²) -E (y)]²
= 2/p² - 1/p - (1/p)²
= q/p²
Answer:
4.56, 4,65, 5,46, 5.64, 6.45 and 6.54
Step-by-step explanation:
start with the whole number and find the smallest one!
It would be 4 then find the number with the smallest amount
Keep doing this to all of the numbers
The right answer for the question that is being asked and shown above is that: "Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis." The description best describes the solution to the system of equations is that <span>Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis</span>