The perimeter of the park is 3x^2 + 37x - 4
<h3>How to determine the perimeter?</h3>
The side lengths of the triangular park are:
10x + 3x^2 - 8, 12x and 15x + 4
Add these sides to determine the perimeter
P = 10x + 3x^2 - 8 + 12x + 15x + 4
Collect the like terms
P = 3x^2 + 10x + 12x + 15x - 8 + 4
Evaluate the sum
P = 3x^2 + 37x - 4
Hence, the perimeter of the park is 3x^2 + 37x - 4
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Answer:
t = 13.1576 years
Step-by-step explanation:
The situation can be modeled as
P = Po.(1-r)^t
Where
t is the years transcurred
Po is the initial amount
r is the rate of change
Po = 40000
r = 10% equivalent to 0.1
Now
A quarter of the original amount
(1/4)*Po = Po.(1-r)^t
(1/4) = (0.9)^t
t = 13.1576
Please, see attached picture
![\dfrac{\sqrt[3]{x+h}-\sqrt[3]x}h\times\dfrac{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}{\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}}=\dfrac{(\sqrt[3]{x+h})^3-(\sqrt[3]x)^3}\cdots](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%2Bh%7D-%5Csqrt%5B3%5Dx%7Dh%5Ctimes%5Cdfrac%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7Bx%28x%2Bh%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7Bx%28x%2Bh%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D%7D%3D%5Cdfrac%7B%28%5Csqrt%5B3%5D%7Bx%2Bh%7D%29%5E3-%28%5Csqrt%5B3%5Dx%29%5E3%7D%5Ccdots)

The

s then cancel, leaving you with the
![\cdots=\sqrt[3]{(x+h)^2}+\sqrt[3]{x(x+h)}+\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Ccdots%3D%5Csqrt%5B3%5D%7B%28x%2Bh%29%5E2%7D%2B%5Csqrt%5B3%5D%7Bx%28x%2Bh%29%7D%2B%5Csqrt%5B3%5D%7Bx%5E2%7D)
term.
If it's not clear what I did above, consider the substitution
![a=\sqrt[3]{x+h}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7Bx%2Bh%7D)
and
![b=\sqrt[3]x](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5Dx)
. Then

Answer:
a. mean = 1000
standard deviation = 4358.9
b. expected value of average damage bar Y = 1000
probability bar y exceeds 2000 = 0.011
Step-by-step explanation:
we have p1 = 95%, y1 = 0, p2 = 5%, y2 = 20000
Mean = (0.95 * 0) + (0.05 * 20000)
= 1000
var(y) = E(y²) - E(Y)²
= we solve for E(y)²
= 0²*0.95 + 20000²*0.05
= 0 + 20000000
then the variance of y = 20000000 - 1000²
=20000000-1000000
= $19000000
standard deviation is the square root of variance
= √19000000
= 4358.9
2.
a. Expected value of average is also the mean = 1000
b. we are to find probability that barY exceeds 2000

= 1000/435.889
= 2.29
1-p(z≤2.29)
= 1 - 0.989
= 0.011
so the probability that barY exceeds 2000 is 0.011
Answer c
Step-by-step explanation: