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GalinKa [24]
3 years ago
9

Which of the following statements is true?

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0
If my memory serves me well, the only wtatement which is true is the last one: <span>D) All linear equation and all quadratic equations are polynomial equations.</span>
Scrat [10]3 years ago
5 0

Answer:

D) All linear equation and all quadratic equations are polynomial equations.

Step-by-step explanation:

Before a few  weeks ago I got a packet with that question and I answered with D. I ended up with a 90% but I got that question right. Hope it helps :)

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Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.
Sladkaya [172]

Answer:

The solution is  \frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

Step-by-step explanation:

From the question

    The function given is  f(x) =  \frac{e^{2x}}{ 25 + e^{4x}} dx

The  indefinite integral is  mathematically represented as

          \int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx

Now  let  e^{2x} =  u

=>   \frac{du}{dx} 2e^{2x}

=>   2 e^{2x}dx =  du

So

\int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx =  \int\limits  {\frac{1}{ 2(25 + u^2)} } \, du

= \frac{1}{2} \int\limits  {\frac{1}{ 25 + u^2)} } \, du

=  \frac{1}{2} \int\limits  {\frac{1}{ 5^2 + u^2)} } \, du

= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5}  +  C

Now substituting for  u

\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

3 0
3 years ago
10 - 5 2/3 = ? not in decimal form only fraction .
Dmitrij [34]

it would equal the same mixed number. 5 2/3

3 0
2 years ago
Read 2 more answers
In triangle PQR point c is the centroid if PQ= 30 then PX=
vova2212 [387]

Answer:

15

Step-by-step explanation:

since c is the centroid, therefore PX=XQ=1/2 x PQ

∴ PX=15

3 0
3 years ago
On Saturday afternoon, Armand sent m text
Paladinen [302]

Answer:

5m + 4p

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the rate of change of y with respect to x for this function?​
lilavasa [31]

Answer:

Given the function: y=f(x) = 3x+2

when x=-2 at the beginning of the interval [-2, 5],

then;

y = 3x+2 begins at

y= 3(-2)+2 = -6+2= -4.

and

when x=5 at the end of the interval [-2, 5],

y = 3x+2 ends up at

y= 3(5)+2 = 15+2= 17.

So,

y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21

and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7

So, the average rate of change of y with respect to x over the interval

[-2, 5] is given by ;

=

Therefore, the average rate of change y with respect to x over the interval is, 3

Step-by-step explanation:

4 0
2 years ago
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