Answer:
Both are inverse pairs
Step-by-step explanation:
Question 11

(a) Rename g(x) as y

(b) Solve for x :

(c) Multiply each side by ⅝

(d) Switch x and y

(e) Rename y as the inverse function

(f) Compare with your function

f(x) and g(x) are inverse functions.
The graphs of inverse functions are reflections of each other across the line y = x.
In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)
Question 12
h(x)= x - 2
(a) Rename h(x) as y
y = x - 2
(b) Solve for x:
x = y + 2
(c) Switch x and y
y = x + 2
(e) Rename y as the inverse function
h⁻¹(x) = x + 2
(f) Compare with your function
f(x) = x + 2
f(x) = h⁻¹(x)
h(x) and ƒ(x) are inverse functions.
The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).
Answer:
0.14
Step-by-step explanation:
From the question given above, the following data were obtained:
Grade A = 5
Grade B = 10
Grade C = 15
Grade D = 3
Grade F = 2
Sample space (S) = 35
Probability of getting grade A, P(A) =?
The probability that a student obtained a grade of A can be obtained as follow:
Probability of getting grade A, P(A) =
Event of A (nA) / Sample space, (nS)
P(A) = nA/nS
P(A) = 5/35
P(A) = 0.14
Thus, probability that a student obtained a grade of A is 0.14
You can treat x and 2x+1 just as though they are real numbers.
So f(2x+1) = 3(2x+1) - 5 = 6x + 3 - 5 = 6x - 2
In the above, I made use of something called the distributive law which says that if a,b and c are real numbers, then a(b+c) = ab + ac.