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ahrayia [7]
3 years ago
6

How much water should be added to 70ml of 60 percent acid solution to dilute it to a 50 percent acid solution?

Chemistry
1 answer:
mestny [16]3 years ago
7 0

Answer:

14 ml of water

Explanation:

To find the volume you need to dilute the concentration of a solution, you should use the formula C1 x V1 = C2 x V2 in which:

C1 = initial concentration ( in this case 60 %)

V1 = initial volume ( in this case 70 ml)

C2 = Final concentration ( you want to dilute until 50 %)

V2 = final volume ( the variable you want to search)

So you need to:

1.- Isolate the variable you want to find: V2 = (C1 x V1) / C2

2.- Substitute data: V2 = (60% x 70 ml) /50 %

3.- You do the math, in this case is 84 ml.

4.- Remember that you have a initial volume of 70 ml, so the difference (84 ml - 70 ml = 14 ml) is the volume you need to add to dilute your solution.

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General Formulas and Concepts:

<u>Gas Laws</u>

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<u>Stoichiometry</u>

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  • Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

0.500 mole Xe (g)

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                  \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)
  2. [DA] Evaluate:                                                                                               \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}

Topic: AP Chemistry

Unit: Stoichiometry

3 0
2 years ago
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