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3 years ago

Which of these would DECREASE the solubility of a solid in water?

Chemistry

1 answer:

stepladder [879]3 years ago

6 0

Answer: B) Increasing the air pressure

Explanation:

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4) Calculate the percentage by<br> mass of oxygen in Pb(NO3)2<br> A) 193<br> B20<br> 145

Ierofanga [76]

Answer:

im getting 331.23

Explanation:

Element Number Mass Percet Composition

O 6 16.00 28.9828819853274

N 2 14.01 8.45937867946744

Pb 1 207.21 62.5577393352051

5 0

3 years ago

student in chemistry 150-02 weighed out 55.5g of octane c8h18 and allowed it to react with oxygen, o2 the product formed were ca

Tasya [4]

Answer:

C8H8 + 10O2 → 8CO2 + 4H2O

Explanation:

unbalanced reaction:

C8H8 + O2 → CO2 + H2O

balanced for semireactions:

(1) 16H2O + C8H8 → 8CO2 + 40H+

(2) 10(4H+ + O2 → 2H2O)

⇒ 40H+ + 10O2 → 20H2O

(1) + (2):

balanced reaction:

⇒ C8H8 + 10O2 → 8CO2 + 4H2O

8 - C - 8

20 - O2 - 20

8 - H - 8

3 0

4 years ago

How do you know if a equation is balanced or unbalanced

denpristay [2]

A chemical equation is only balanced once there are equal numbers of all types of element on both sides of the equation

7 0

3 years ago

90 POINTSSSS!!!

Katarina [22]

Answer:

$\large \boxed{\text{-2043.96 kJ/mol}}$

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)

Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}$

(b)Total enthalpies of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}$

ΔᵣH° is negative, so the reaction is exothermic.

5 0

3 years ago

What is the mass of 5.80x10^23 atoms of silver

Natasha_Volkova [10]

Answer:

follow me and mark me brainliest

6 0

3 years ago