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2 years ago

11

Calculate the molar solubility of pbi2 in the presence of 0.10 m nai.

1 answer:

lys-0071 [83]2 years ago

5 0

The equation representing the solubility of $PbI_{2}$ :

$PbI_{2}(aq)Pb^{2+}(aq) + 2 I^{-}(aq)$

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A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the

tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

$0.143-0.1271=0.0159$

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

$0.0159/16.00=9.94*10^{-4}$

There are 9.94*10^-4 moles of Oxygen.

6 0

1 year ago

Predict the whether the following reactions are possible or not.

vova2212 [387]

Answer:

1. No

2. No

3. Yes

4. No

5. Yes

6. No

Explanation:

Use the reactivity series. If the element is above it, it is more reactive. More reactive elements can displace less reactive elements from their compounds.

5 0

3 years ago

Can someone please give me a clear definition of what ceramics are? It will really help! :)

natima [27]

The pots and other articles made from clay hardened by heat is called ceramics..

HOPE IT'S HELPFUL FOR U MATE!!!!

8 0

3 years ago

Read 2 more answers

A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

3 0

3 years ago

3.What is evaporation?

djverab [1.8K]

Evaporation is the change from a liquid to gas

6 0

2 years ago