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Sunny_sXe [5.5K]
3 years ago
15

Show workk!!! pls

Chemistry
1 answer:
Dimas [21]3 years ago
6 0

Answer:

2.2moles

Explanation:

Given parameters:

Atomic mass of Radium = 226

Mass of Radium  = 497.2g

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we use the expression below:

    Number of moles  = \frac{mass}{molar mass}

The molar mass of the radium   = 226g/mol

So;

       Number of moles  = \frac{497.2}{226}   = 2.2moles

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Balance the double replacement: <br> Mn(SO4)2 + K2S2O3 =
Firlakuza [10]

Answer:

        Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

Explanation:

Reaction Given:

              Mn(SO₄)₂ + K₂S₂O₃ =

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the Sulfur at the reactant side is 6, the number of Sulfurmust be 6 on the product side.

First we Complete the reaction

                  Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal, then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

             Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Number of atoms of Reactant:

Mn = 1

S = 4

O = 7

K = 2

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

So this is not a balance equation as the atoms of the reactant atoms not equal to the number of the product atoms.

As there are 4 Sulfur, and 7 oxygen atoms at reactant side but 5 Sulfur, and 10 oxygen atoms at the product side so we balance this along with other

Balanced Equation:

          Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

Now count the number of atoms of reactant and product

Number of atoms of Reactant:

Mn = 1

S = 6

O = 14

K = 4

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

Now this reaction is balanced as the atoms of the reactant atoms equal to the number of the product atoms.

So,

the Coefficient of  K₂S₂O₃ and K₂SO₄ is 2 in balanced equation

4 0
3 years ago
What does chlorine (Cl-) do for sodium (Na+)? What tasty substance is produced when this
solong [7]
Pretty sure it’s salt
7 0
3 years ago
When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because:
noname [10]

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Explanation:

When hydrogen reacts with nitrogen, ammonia is formed as shown below;

3H₂ (g) + N₂ (g) → 2NH₃ (g)

As seen from the equation, every 3 moles of H₂ react with a mole of N₂ to form 2 moles of NH₃.

The limiting factor in a chemical reaction is the reactant that gets depleted first.

Because the molar mass of nitrogen gas is approximately 28g/mol, 70g of nitrogen gas would be 2.5 moles.

The reaction ratio of nitrogen to hydrogen in the reaction is 1 : 3. The reaction would require 2.5 * 3 (7.5) moles of hydrogen for a complete reaction.

However since there are only 7g on hydrogen, (Remember 1 mole of H₂ is approximately 2g), the available moles of H₂ is 7 / 2 = 3.5

3.5 moles fall short of the 7.5 moles of H₂ required for a complete reaction. H₂ gets depleted first before N₂.  The reaction would require 4 more moles of H₂.

6 0
3 years ago
Analysis of a 10.15 g sample of a compound known to contain only phosphorus and oxygen indicates a phosphorus content of 4.433 g
Anna007 [38]

find mass of oxygen by subtracting mass of phosphorus from the total mass

divide the masses by the molar mass to get moles

divide moles by the smallest amount of moles

multiply by 2 to get a nice number

P4O5

5 0
3 years ago
A) The lab tech called in sick today and you are called in to help prepare
jarptica [38.1K]
<h3>Answer:</h3>

318.405 g

<h3>Explanation:</h3>

We are given;

  • Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
  • Molarity of the solution to be prepared as 2.00 M

We are required to determine the mass of K₃PO₄ to be measured.

<h3>Step 1: Determine the number of moles of K₃PO₄</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

                          = 1.5 moles

<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

                        = 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

7 0
3 years ago
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