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Bond [772]
3 years ago
8

HELP! DUE TODAY!! Will give brainiest

Mathematics
1 answer:
inna [77]3 years ago
6 0

Answer:

the equation is y=0.5x-2

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Tammy is making 5 batches of punch for the school's Spring Carnival. The recipe for one batch uses 1 liter of orange juice, 550
NISA [10]
Alright, so look. This is one of the probably many ways you can do this. And this is how I used to do my stuff. So watch:

First change the mL to liters:
Orange Juice: 1L
Lemon juice: 550mL=0.55L
Soda Water: 2.6L
Apple cider: 2*750=1500mL=1.5L

Then add them all together:
1+0.55+2.6+1.5=5.65

Lastly, multiply that number by 5:
5.65*5=28.25

Tammy will make 28.25 Liters of punch.

So Answer = 28.25 liters of punch
5 0
3 years ago
Which of the following shows that the product of two irrational numbers can be rational?
sergij07 [2.7K]
I think it’s C from my experience
5 0
3 years ago
Solve y=x^2+2 for x.
11Alexandr11 [23.1K]
X^2= 2-y

x= √(2-y) is the solution to the problem
5 0
3 years ago
1.Your primary job’s gross income is $3,500.00/month, and your second job’s realized income is $368.49/month. Deductions are FIC
bazaltina [42]
Part 1
Total income per month = $3,500+$368.49 = $3,868.49
Total deductions = 7.65%+10.75%+8.35% = 26.75% = 0.2675

Net income = Total income - Deductions = Total deductions (1-0.2675) = $3,868.49 (1-0.2675) = $2,833.67

Part 2
Fixed expenses = $1,035.65 which is 36% of realized income.

Then, if realized income is 100%;
$1,035.65 ------------------ 36%
$ Realized income ----- 100%
Therefore,
Realized income = 1,035.65*100/36 = $2,876.81
3 0
3 years ago
Determine the degree of the given polynomial x^2 ( 1 - x^3)
Ray Of Light [21]

Answer:

\huge\boxed{\bf\:5}

Step-by-step explanation:

Polynomial = x^{2} (1 - x^{3}).

Before determining the degree of the polynomial, let's open the parentheses using the distributive property .

x^{2} (1 - x^{3})\\=\underline {x^{2} - x^{5}}

Degree is the highest exponential power in a polynomial  .

So, the degree of the given polynomial is 5.

\rule{150pt}{2pt}

4 0
2 years ago
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