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wel
3 years ago
6

Find the value of a for which the solution of the inequality is all real numbers

Mathematics
1 answer:
Katen [24]3 years ago
8 0

Answer:

a= \frac{4x+15}{x-3}

Step-by-step explanation:

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PLEASE HELP 0ffering MAX POINTS
Mkey [24]

Answer:

Priya is correct

Step-by-step explanation:

Priya is right because of the plus sign. When its adding you should always subtract from both sides but when you have the subtraction side you have to add to both sides.

7 0
2 years ago
Read 2 more answers
]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf
Anna35 [415]

Answer:

\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

Step-by-step explanation:

Circumference of circle =\pi \cdot d

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to \frac{360^{\circ}}{n^{\circ}}

So, Number of sectors =  \frac{360^{\circ}}{n^{\circ}}

The arc length of each sector is the circumference divided by the number of sectors

\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}

Diameter d = 2r (r = radius)

\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}

Option b is true

Hence\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

7 0
3 years ago
At what distance along the central perpendicular axis of a uniformly charged disk of radius 0.600 m is the magnitude of the elec
Vesna [10]
Khrewrftw5elytg00<span>At what distance along the central perpendicular axis of a uniformly charged disk of radius 0.600 m is the magnitude of the electric field equal to one half the magnitude of th</span>
7 0
3 years ago
WILL GIVE BRAINLIEST
sveticcg [70]
The answer is 2x15 which is 30ft
3 0
2 years ago
Explain or show how you could find 5÷13
OverLord2011 [107]

Answer:

bus stop division really hard to show on here.

13/5

13 does not go into 5 so put a decimal point after the 5

13/5.000 carry the 5 over to the zero

13 goes into 50 3 times with 11 left over. carry the 11 over to the next zero. 13 goes into 110 8 times with 6 left over. carry over to the next zero. keep adding zeros and carrying over until the 13 goes into a number equally.

the answer is 0.38461538

3 0
3 years ago
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