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2 years ago

WILL GIVE BRANLIEST AND 30 POINTS!! Please help!

1 answer:

8 0

Phase changes happen as the temperature changes.
All matter can move from one state to another. It may require extreme temperatures or extreme pressures, but it can be done. Sometimes a substance doesn't want to change states. You have to use all of your tricks when that happens. To create a solid, you might have to decrease the temperature by a huge amount and then add pressure. For example, oxygen (O2) will solidify at -361.8 degrees Fahrenheit (-218.8 degrees Celsius) at standard pressure. However, it will freeze at warmer temperatures when the pressure is increased.

You might be interested in

A naoh (aq) stock solution was created by dissolving 3.88 g naoh in water to create a 100.00 ml solution. what is the concentrat

Bess [88]

0.0381g/mL will be concentration of this solution

The ratio of a solute—a substance that dissolves—to a solvent—a substance that does not dissolve—determines the concentration of a solution in chemistry. C = m/V, where C is the concentration, m is the mass of the solute dissolved, and V is the overall volume of the solution, is the accepted formula.

How to reach the solution?

First find for the density of NaOh which is 2.13 g/cm3

3.88 ÷ 2.13 = 1.82mL

100mL + 1.82mL = 101.82mL

3.88 ÷ 101.82mL = 0.0381g/mL

More about NaOh:

The extremely adaptable chemical sodium hydroxide (NaOH), sometimes referred to as caustic soda or lye, is employed in a range of manufacturing processes. A byproduct of the manufacturing of chlorine is sodium hydroxide. Numerous items that are used on a daily basis, including paper, metal, drain and oven cleansers for industry, soap, and detergents, are made with sodium hydroxide.

Learn more about Naoh here:

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5 0

1 year ago

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

2 years ago

A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te

Monica [59]

You can establish a system of two equation with two variables.

Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution

Equations:
Balance of sugar:

Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63

1) 0.5V1 + 0.8V2 = 63

Final volume = volume of 50% solution + volume of 80% solution

2) V1 + V2 = 105

From (2) V1 = 105 - V2

Substitue in (1)

0.5 (105 - V2) + 0.8 V2 = 63

52.5 - 0.5V2 + 0.8V2 = 63

0.3 V2 = 63 - 52.5

0.3 V2 = 10.5

V2 = 10.5/0.3
V2 = 35mL

V1 = 105 - 35 = 70 mL

Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.

5 0

3 years ago

If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n)?

vekshin1

If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.

These consist of glycogen, cellulose, as well as starch. Benedict's reagent can be used as a test to see if there are lots of simple carbohydrates present. When it interacts with lowering sugars, it changes from turquoise to yellow or orange. These contain unbound aldehyde but rather ketone groups in simple carbohydrates.

Sugars and starches are examples of carbohydrates. They contain carbon, hydrogen, and oxygen, which appear in the ratio 1:2:1. Size-based categories for carbohydrates include monosaccharides, disaccharides, or polysaccharides. Carbohydrates act as sources of power as their main purpose.

Therefore, If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.

To know more about carbohydrate

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4 0

9 months ago

Sulfur (S) and oxygen gas (02) undergo a chemical<br> reaction to form sulfur trioxide (SO3).

Dvinal [7]

Answer:

Explanation:

I just think it is the right answer :) Sorry if I am wrong..

8 0

2 years ago