Answer: nop
Step-by-step explanation:
Answer:
23. x = 4; DE = 44
24. x = 25; DS = 28
Step-by-step explanation:
23. Point S is the midpoint of DE, so ...
DS = SE
3x +10 = 6x -2
12 = 3x . . . . . . . . . add 2-3x
4 = x . . . . . . . . . . . divide by 3
Then DS has length ...
DS = 3x +10 = 12 +10 = 22
and DE is twice that length, so ...
DE = 44
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24. DS is half the length of DE, so is ...
DS = DE/2 = 56/2
DS = 28
Then x can be found from ...
DS = x +3
28 -3 = x = 25 . . . . . substitute value for DS
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<em>Comment on problem 24</em>
Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.
Answer:
516 inches
Step-by-step explanation:
2(8(6)) + 2(15(6)) + 2(15(8))
96 + 180 + 240 = 516in
The answer is 516in
*Please mark me the brainliest. Thanks
Step-by-step explanation:
g(x) = 3x² + 2x - 1
g(-1) = 3(-1)² + 2(-1) - 1
= 3(1) -2 -1
= 3 - 3
= 0
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.