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olya-2409 [2.1K]
3 years ago
13

A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th

e food taken by each man is almost the same.​
Mathematics
1 answer:
mestny [16]3 years ago
6 0

Let x be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

400\cdot 40\cdot x = 16000x

After 10 days, the 400 men will have consumed

400\cdot 10\cdot x = 4000x

food, impliying that the food remaining is

16000x-4000x=12000x

If 200 more men join the garrison, there are now 600 men. Each of them requires x food each day, and there are 12000x units of food remaining. They will last

\dfrac{12000x}{600}=20 days.

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Solve for x.5(x – 10) = 30 – 15x
nlexa [21]
5(x-10)=30-15x

5x-50=30-15x

20x=30+50
x=4.
6 0
3 years ago
PLEASE HELP HEHE!
storchak [24]

Answer:

5%

Step-by-step explanation:

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3 years ago
Can somebody please help me with this question?
Aliun [14]

Answer:

120, 114, 126

Step-by-step explanation:

Since these are all exterior angles, they will all always add up to 360°. Since we know this, you can set up an equation and it would be x+(x+6)+114=360. When added you get 2x+120=360. Now subtract 120 on each side to get 2x equals 240. Then you divide by 2 and get that x is 120. Now all you have to do is plug x into the equations for the angles so they would be 120, 114, and 120+6 so 126. Now you have 120,114,and 126 as your angles. To check, just add all the angle measurements up and it should equal 360.

4 0
3 years ago
Read 2 more answers
HELP.
Viefleur [7K]

Answer:

The number of cases in the year 2010 is 266.

Step-by-step explanation:

An exponential function is one that the independent variable x appears in the exponent and has a constant a as its base. Its expression is:

f(x)=aˣ

being a positive real, a> 0, and different from 1, a ≠ 1.

In this case:

r(t) = 207*e^{0.005*t}

where t is the number of years since 1960 and   e is an irrational number of which it is not possible to know its exact value because it has infinite decimal places. The first figures are 2,7182818284590452353602874713527 and is often called the Euler's number. e is the base of natural logarithms.

In this case, you want to know the number of cases r (t) in 2010. So, to know t you must know how many years have passed since 1960. For that, you can simply do the following subtraction: 2010-1960 and you get as a result : 50.

Replacing in the exponential expression r (t):

r(t) = 207*e^{0.005*50}

Solving:

r(t)=265.79 ≅ 266

<u><em>The number of cases in the year 2010 is 266.</em></u>

4 0
3 years ago
Questions in Image below. Please explain how you got your answers in depth please.
irakobra [83]

Step 1

Revenue (sometimes referred to as sales revenue) is the amount of gross income produced through sales of products or services. This, in the context of the question, means that the revenue generated from the sales of tickets is given by the function below. We are now required to find the price that tickets will be sold at in a day based on the function that will make the revenue to be equal to $0.

The revenue is given by the function;

\begin{gathered} f(p)=150p-5p^2 \\ f(p)\text{ is the revenue and should be equal to 0 according to the question.} \\ p=\text{ The price of tickets for the day for the revenue to be 0} \end{gathered}

To solve this problem or to find this price at which tickets will be solved to give us zero revenue, we must equate the given function for the revenue to 0 and find the value of p, the price of the tickets that make the function to be equal to 0.

For the theatre to make $0 in revenue, this means f(p)=0.

Therefore, we will equate f(p) to 0

Step 2

Equate f(p) to 0

\begin{gathered} 0=150p-5p^2 \\ p(150-5p)=0----(\text{factorize)} \\ p=0 \\ 0r \\ 150-5p=0 \\ 150=5p \\ \frac{5p}{5}=\frac{150}{5} \\ p=30 \\ p=0\text{ or 30} \end{gathered}

Therefore the revenue to be zero, the price of the ticket will be $0 or $30 but the question asked us how high the ticket price will be to get a revenue of 0. Both 0 and 30 gave us revenue of 0 but $30 is higher therefore, the answer will be $30.

Check;

\begin{gathered} 150p-p^2=0 \\ \text{If the price of tickets=0} \\ 150(0)-5(0^2)=0 \\ \text{If p=30} \\ 150(30)-5(30^2)=4500-4500=0 \end{gathered}

Both give us 0 revenue but $30 is higher and the right answer.

Step 3

The equation you can write for revenue of $700 is;

\begin{gathered} 700=150p-5p^2 \\ 5p^2-150p+700=0_{} \end{gathered}

6 0
1 year ago
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