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jok3333 [9.3K]
2 years ago
7

Help needed ASAP please please

Mathematics
2 answers:
Juliette [100K]2 years ago
5 0

Answer: the third answer

Step-by-step explanation:

Alex Ar [27]2 years ago
3 0
It is the third oneeee
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Help me answer this thanks
patriot [66]
The first fourth and sixth would be the answer
3 0
3 years ago
01:
Jobisdone [24]

Answer:

4

Step-by-step explanation:

4 0
2 years ago
In regina, saskatchewan, the average mid-afternoon temperature in january is -12.6°C.The average mid afternoon temperature in ju
Andrews [41]

Finding the difference between the two temperatures, it is found that Regina is 38.7ºC degrees colder in January than in July.

----------------------------

  • The mid-afternoon temperature in January is of -12.6ºC.
  • In July, it is of 26.1ºC.
  • The difference of the temperatures is given by:

26.1 - (-12.6) = 26.1 + 12.6 = 38.7

From the difference of 38.7ºC, there are two interpretations:

  • Regina is 38.7ºC degrees colder in January than in July.
  • Regina is 38.7ºC degrees warmer in July than in January.

A similar problem is given at brainly.com/question/22136310

6 0
2 years ago
The sum of the 13th square number and the 4th cube number?
Gemiola [76]

Answer:

13th square number+4th cube number=233

Step-by-step explanation:

13^{2} +4^{3}=233

4 0
3 years ago
If an object is dropped from a height of 55 feet, the function d=-16t^2+55 gives the height of the object after t seconds. Graph
Ymorist [56]
Notice, it hits the ground when d = 0, thus 

\bf \stackrel{d}{0}=-16t^2+55\implies 16t^2=55\implies t^2=\cfrac{55}{16}\implies t=\sqrt{\cfrac{55}{16}}

that's when.

as far as its graph, is more or less like the picture below, now, notice that if we put the quadratic in "vertex form", it'd look like 

\bf d=-16t^2+55\implies d=-16(t-\stackrel{h}{0})^2+\stackrel{k}{55}\qquad vertex~(h,k)

so its vertex is at (0, 55), so just pick one point to the left of the vertex, and one to the right of the vertex, and draw it away

8 0
3 years ago
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