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vova2212 [387]
3 years ago
5

Someone help me leran this meth problem

Mathematics
2 answers:
Sergio [31]3 years ago
3 0

Answer:


Step-by-step explanation:


mestny [16]3 years ago
3 0

Answer:

y = -2x + 28

Step-by-step explanation:

We are given the slope and a point on the line so first we use the point-slope form :-

y - y1 = m(x - x1)

Substituting the given values:-

y - 12 = -2(x - 8)

Now convert to the slope-intercept form (which is y = mx + c):-

y = -2x + 16 + 12

y = -2x + 28   (answer)

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\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y

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\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill

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