If AM=10, then AC=10 because both are radii. TC is a diameter so that’ll just be the radius doubled. TC=20!
D. 4.81 x 10^13
Move the decimal to the right 13 times, because when you multiply by 10, you make the number bigger, when you divide you move the decimal to the left to make the number smaller.
48,100,000,000,000
Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
Answer:
∠A = ∠B = 80°
Step-by-step explanation:
The angles are corresponding angles where a transversal crosses parallel lines, so are congruent. That means ...
∠A = ∠B
8x -8° = 5x +25° . . . . . substitute the given expressions
3x = 33° . . . . . . . . . . . . add 8°-5x
x = 11° . . . . . . . . . . . . . . divide by 3
Then the angles are ...
8·11° -8° = 80°
