20 ft because the shadow would be 3/2 of the height. 9 is 3/2 of 6 so the height would be 20 bc 30 is 3/2 of 20
Answer:
295.2
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
Substitute 1 in place of x and the result is -4.
Again substitute 3 in place of x and the result is 6.
Change=6-(-4)=10
Answer:
328 feet
Step-by-step explanation:
From a boat ont he lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)
Step 1
Note that
that 11°50' is just 11 degrees and 50 minutes
60 minutes = 1 degree,
thus 50 minutes = x degree
50/60 degrees
= 0.83°
Hence: 11°50' = 11.83°.
Step 2
We solve using Trigonometric function of tan
tan theta = Opposite/Adjacent
theta = 11.83°
Adjacent = 1568 feet
Opposite = Height of the cliff = x
tan 11.83° = x/1568
Cross Multiply
x = tan 11.83 × 1568
x = 328.429195 feet
Approximately = 328 feet
The height of the cliff is 328 feet
