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3 years ago

Help pleaseeeeeeeeeeeeeee

Mathematics

1 answer:

Anni [7]3 years ago

4 0

Answer:

Step-by-step explanation:

The top vertex of the triangle on the right is 51° ( alternate angle to 51°

The sum of the 3 angles in a triangle = 180° thus

51 + 72 + y - 6 = 180 , that is

y + 117 = 180 ( subtract 117 from both sides )

y = 63 , then

y - 6 = 63 - 6 = 57

------------------------------

x - 5 , 51 and y - 6 lie on a straight line , therefore

x - 5 + 51 + y - 6 = 180

x - 5 + 51 + 57 = 180

x + 103 = 180 ( subtract 103 from both sides )

x = 77

Thus x = 77 , y = 63 → b

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x^2 - 6x + 9

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(x - 3)^2

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Ivanshal [37]

Answer:

Product A performed better in the study because only 30% failed to get relief with this product, whereas 39% failed to get relief with Product B.

Step-by-step explanation:

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3 years ago

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Answer:

x is all real numbers.

Step-by-step explanation:

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4 years ago

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<img src="https://tex.z-dn.net/?f=%7C%5Cfrac%7Bx%2B1%7D%7Bx-1%7D%2B1%7C%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%7Bx%2B1%7D%7Bx-1%

VMariaS [17]

The inequality boils down to

|y| > y

By definition of absolute value, we have

• |y| = y if y ≥ 0

• |y| = -y if y < 0

So if y ≥ 0, we have

y > y

but this is a contradiction.

On the other hand, if y < 0, we have

-y > y ==> 2y < 0 ==> y < 0

and no contradiction.

Now replace y with (x + 1)/(x - 1) + 1. Then you're left with solving

(x + 1)/(x - 1) + 1 < 0

(x + 1 + x - 1)/(x - 1) < 0

2x/(x - 1) < 0

The left side is negative if either 2x > 0 and x - 1 < 0, or 2x < 0 and x - 1 > 0. The first case reduces to x > 0 and x < 1, or 0 < x < 1. In the second case, we get x < 0 and x > 1, but x cannot satisfy both conditions, so we throw this case out.

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