Answer:
<em>The vertical distance in feet that the plane traveled was 4 Km</em>
Step-by-step explanation:
<u>The Slope of a Line
</u>
Suppose we know a line passes across points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:
![\displaystyle m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
The airplane ascent will be modeled with the equation of a line because we are given a constant slope of m=2/3. We also know the horizontal distances are x1=1 Km and x2=7 Km. Substituting in the formula above:
![\displaystyle \frac{2}{3}=\frac{y_2-y_1}{7-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7By_2-y_1%7D%7B7-1%7D)
Operating:
![\displaystyle \frac{2}{3}=\frac{y_2-y_1}{6}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7By_2-y_1%7D%7B6%7D)
Solving for y2-y1, we get the vertical distance traveled by the plane:
![\displaystyle y_2-y_1=6*\frac{2}{3}=4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y_2-y_1%3D6%2A%5Cfrac%7B2%7D%7B3%7D%3D4)
Thus, the vertical distance in feet that the plane traveled was 4 Km
Answer:
A. i believe
Step-by-step explanation:
Based on the formula given for the model of the average cost of tuition and fees, the average cost of tuition in 2010 was $25,858.
<h3>What was the average cost of tuition at private colleges in 2010?</h3>
The base year is 2000 and x denotes the number of years after 2000.
The value of x for 2010 is therefore:
= 2010 - 2000
= 10 years
The average cost of tuition in 2010 is therefore:
= 26 (10)² + 814(10) + 15,118
= 2,600 + 8,140 + 15,118
= $25,858
Find out more on projected costs of tuition at brainly.com/question/12662012
#SPJ1
Answer:
<u>point-slope form:</u> y - 0 = ½(x - 3)
Step-by-step explanation:
Given the slope, m = ½, and the x-intercept, (3, 0):
We can substitute these values into the point-slope form:
y - y1 = m(x - x1)
y - 0 = ½(x - 3) ← This is the point-slope form.
If ever you need to transform the point-slope form into its slope-intercept form, y = mx + b:
Distribute ½ into the parenthesis:
y - 0 = ½(x - 3)
y = ½x - 3/2 (this is the slope-intercept form).