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kakasveta [241]

3 years ago

8

The Census Bureau wants to conduct a survey to determine the percentage of adults that buy clothing online. How many adults do t

hey need to survey in order to be confident that the sample proportion is in error by no more that 2 percentage points.

1 answer:

Ivan3 years ago

4 0

Answer and explanation:

Please find attached answer and explanation

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A, b, c, or d?? im so bad at this dont even try me

Vika [28.1K]

The median is 7. By definition of "median," half of the data values are below 7; half are above 7. Thus, the first statement is FALSE.

Spread: in the 2nd statement we are comparing the spread from lower quartile (4) to the median (7) and that from the median (7) to the upper quartile (9). In other words, we're comparing 3 to 2. This statement is TRUE.

The 3rd statement is the opp. of the 2nd statement, and thus is FALSE.

The 4th statement is FALSE. See my comments regarding the 1st statement.

8 0

3 years ago

4.26 rounded to the tenths place

Vadim26 [7]

It would become 4.3 because 6 is 5 or greater so you round up.

7 0

3 years ago

Read 2 more answers

What values of b satisfy 3(2b + 3)2 = 36?

Vlad1618 [11]

Exact Form:

b = 3/2

Decimal Form:

b = 1.5

Mixed Number Form:

b = 1 1/2

Hope This Helps You!

Please mark as brainlest if possible!

6 0

3 years ago

Find the critical points, domain endpoints, and local extreme values for the function

aliina [53]

Answer:

a) $x = -3$ , b) $x = 0$ , $x = -6$ , c) $x = 0$ , d) $x = -6$

Step-by-step explanation:

a) Let derive the function:

$f'(x) = \frac{10\cdot x \cdot (x+3)-5\cdot x^{2}}{25\cdot (x+3)^{2}}$

$f'(x)$ is undefined when denominator equates to zero. The critical point is:

$x = -3$

b) $f'(x) = 0$ when numerator equates to zero. That is:

$10\cdot x \cdot (x+3) - 5\cdot x^{2} = 0$

$10\cdot x^{2}+30\cdot x -5\cdot x^{2} = 0$

$5\cdot x^{2} + 30\cdot x = 0$

$5\cdot x \cdot (x+6) = 0$

This equation shows two critical points:

$x = 0$ , $x = -6$

c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that $x = 0$ corresponds to a local maximum. (See Attachment)

d) By plotting the function, it is evident that $x = -6$ corresponds to a local minimum. (See Attachment)

8 0

3 years ago

Write in decimal form:

Nuetrik [128]

This makes no sense could you rewrite it please

6 0

3 years ago