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ivann1987 [24]
3 years ago
13

If ABCDE is reflected over the x-axis and then translated 3 units left, what are

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:

(1, - 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

B(4, 2 ) → (4, - 2 )

A translation of 3 units left means subtract 3 from the x- coordinate of the point.

(4, - 2 ) → (4 - 3, - 2 ) → (1, - 2 )

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what is sum 18+57_<img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%26
REY [17]

Answer:

18+57= 75

Step-by-step explanation:

Next time use a calculator chuckle nuts

7 0
3 years ago
HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
Llana ran 2 laps around the field in 8 minutes. What was he average speed?
olganol [36]

Answer:

40

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I will give brainliest!!!! Which expressions are equivalent to x+x+x+2? Choose 2 answers: A 3x + 2 (Choice B) B 3 + 2x (Choice C
____ [38]

Answer:

the answer is a and d ! hope it help

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How to write Q={1,2,3,5} in set builder form?<br>​
blagie [28]

Answer:

{x:x is a natural number less than 6}

Step-by-step explanation:

Set builder is a type of set where we have to represent any value inside a set

by using the variable x, v, b, a, c etc.

Eg A={1,2,3,4}

For eg {a: a is a natural number less than 5}

8 0
1 year ago
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