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2 years ago

If you have a 2% pay rise on £7 an hour, how much will you get paid an hour?

Mathematics

1 answer:

lidiya [134]2 years ago

8 0

First you need to multiple 7X0.02 and then add that number to 7

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What is the equation of the line that is parallel to the line 5x 2y = 12 and passes through the point (−2, 4)? y = – five-halves

Oduvanchick [21]

Answer:

The answer is

$y = - \frac{5}{2} x - 1$

Step-by-step explanation:

If two equations are parallel it means that both their gradients are equal. We were given the equation:

$5x + 2y = 12$

in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:

$5x + 2y = 12 \\ 2y = 12 - 5x \\ \frac{2y}{2} = \frac{12}{2} - \frac{5}{2} x \\ y = 6 - \frac{5}{2} x \: \\ or \: \\ y = - \frac{5}{2} x + 6$

Therefore the gradient of the parallel line with points (-2, 4) is also -5/2

$y = mx + c \\ 4 = - \frac{ 5}{2} ( - 2) + c \\ 4 = \frac{10}{2} + c \\ 4 = 5 + c \\ 4 - 5 = c \\$

$c = - 1 \\ hence \: the \: equation \: for \: the \: \\ parallel \: line \: is \\ \: y = - \frac{5}{2} x - 1$

8 0

1 year ago

AC=8x–14 and EC=2x+11 find x

BaLLatris [955]

<h2>If AC = 8x-14 and EC = 2x +11, solve for x. %3D В A</h2>

8 0

2 years ago

This experiment was divided into two parts. For the first part of the experiment, the was intentionally manipulated. This was th

prohojiy [21]

Answer:

1. force applied to the cart

2. acceleration of the cart

3. mass of the cart

4. acceleration of the cart

Step-by-step explanation:

correct on edge !

4 0

3 years ago

Read 2 more answers

Fun fact

pav-90 [236]

Answer: wow

I'd want nothing more than to swim in a pool of saliva.

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2 years ago

11000 is compounded semiannually at a rate of 12% for 21 years. Find the total amount in the compound interest account

marishachu [46]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\dotfill &\$11000\\
r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus twice}
\end{array}\dotfill &2\\
t=years\dotfill &21
\end{cases}$

$\bf A=11000\left(1+\frac{0.12}{2}\right)^{2\cdot 21}\implies A=11000(1.06)^{42}\implies A\approx 127127.359416$

5 0

3 years ago