Question

What is the completely factored form of 12xy – 9x – 8y + 6?

Answer 1

(12xy-9x) -(8y+6). <--group them
(12xy - 9x) (8y - 6). <---- switched the sign infront of the , 6 because of the sign outside its perenthesis

3x(4y -3). 2(4y-3). <--gcf of 12xy and 9x is 3x n divided both by 3x n got that n I did the same steps n got the other
(3x+2) (4y-3)<-- o took the ones outside the parenthesis n had them in one together, n the other ones already in the parenthesis looked the same so I picked one..



ans is (3x+2)(4y-3)

hope I helped :)

Answer 2

Answer:

Given that: $12xy -9x -8y +6$

To find the factors of the polynomial with two variables.

(1)

First take the common factor from first two terms.

Common factor from first two terms is, 3x

then, it becomes;

$3x(4y-3)$

(2) Now, again taking the common factor from last two terms.

i,e -2

so, it becomes;

$-2 (4y -3)$

Then, the combined form of the given polynomial

$12xy -9x -8y +6$ is;

$3x(4y-3)-2(4y-3)$

$(4y-3)(3x-2)$

Therefore, the completely factored form of $12xy -9x -8y +6$ is, $(4y-3)(3x-2)$