Step-by-step explanation:
open the bracket
6={(1/5×4y) + 1/5×10}
6=4/5y+2
6-2=4/5y
4=4/5y
divide both sides by 4/5
y=1/5
Answer: 22.5 . The weight of the elephant is "22.5 times greater" than the weight of the lion.
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Explanation:
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(weight of lion) * (x) = (eight of the elephant) ; Solve for "x" .
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→ Divide each side of the equation by "(weight of lion)" ;
to isolate "x" on one side of the equation ; and to solve for "x" ;
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→ (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
(weight of lion) ;
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→ x = (weight of the elephant) / (weight of lion) ;
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→ Plug in our "given values" ; and solve for "x" ;
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→ x = (<span>9*10</span>³) / (4*10²) = (9*10⁽³⁻²⁾) / 4 = (9*10¹) / 4 ;
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→ x = 90 /4 = 25/2 = 22.5 ; which is our answer.
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I'm pretty sure this is the answer but I'm not exactly sure....
Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
Alright, if the original scale was 1 inch = 8 miles, and Dale's house to his school are 1 1/2 inches apart, let's find the amount of miles.
Here's a fast way. 1 inch is 8 miles, and half of 8 equals 4 miles, which is 1/2 of an inch., 8 + 4 = 12 miles.
So if his house and the school were 12 miles apart, and we we're using the 1 inch. = 6 miles scale, then it'd be 2 inches on the map.
How?
If 1 inch. = 6 miles
x inches = 12 miles
12/6 = 2
2 inches = x
