Y+3x=2----equation1
y-2x=-3-----equation 2
e1-e2
(y+3x)-(y-2x)=2-(-3)
y+3x-y+2x=5
5x=5
x=1
sub x=1 into equation 1
y+3(1)=2
y=-1
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
Answer:
Um what was the question?
Step-by-step explanation:
Answer:
D.
It is the graph of f(x) translated 3 units down.
Step-by-step explanation:
