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Ymorist [56]
3 years ago
11

How can poor posture result in back pain?

Physics
2 answers:
pantera1 [17]3 years ago
8 0
A bad posture can result in tight muscles. Flexibility is the capacity to move a joint though it's full range.
Varvara68 [4.7K]3 years ago
5 0

Answer: A-  

Bad posture can result in tight muscles.

Explanation:

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(II) The platter of the hard drive of a computer rotates at 7200 rpm (rpm = revolutions per minute = rev/min). (a) What is the a
Rama09 [41]

Answer:

Explanation:

Given:

Angular velocity, w = 7200 rpm

Radius, r = 3 cm

= 0.03 m

1 bit = 0.5 × 10^-6 m

A.

1 rev = 2pi rad

7200 rev/min × 2pi rad/1 rev × 1 min/60 sec

= 753.98 rad/s

B.

Linear velocity, v = r × w

= 0.03 × 753.98

= 22.62 m/s

C.

1 bit = 0.5 × 10^-6 m

Velocity = 22.62 m/s

1 bit/0.5 × 10^-6 m × 22.62 m/s

= 4.524 × 10^7 bits/s

5 0
4 years ago
A solid cube of aluminum (density of 2.7 g/cm³) has a volume of 0.9 cm³. how many atoms are contained in the cube?​
Reika [66]

Answer:

0.542*10^{23}\ Aluminum\ Atoms

Explanation:

We\ are\ given:\\Density\ of\ aluminum=2.7\ g/cm^3\\Volume\ of\ aluminum-cube=0.9\ cm^3\\Hence,\\As\ we\ know\ that,\\Density=\frac{Mass}{Volume}\\Mass=Density*Volume\\Hence,\ here,\\Mass\ of\ the\ solid\ iron\ cube=2.7*0.9=2.43\ g\\Now,\\We\ also\ know\ that,\\Gram\ Atomic\ mass\ of\ Aluminum = 26.98 \approx 27\ g\\Hence,\\No.\ of\ particles=\frac{Mass}{GAM}*Avagadro's Constant\\Hence,\ here\\No.\ of\ Aluminum\ atoms=\frac{2.43}{27}*6.022*10^{23} \approx 0.542*10^{23}\ Aluminum\ Atoms

8 0
3 years ago
Rest and Motion are the relative term. why? explain with example(please help me (╥﹏╥))​
klemol [59]

Explanation:

it depens on the subject and object. Let's example

you are driving a tesla car with your dog sitting on your side. You will say that the dog is at REST

but your friend, standing in sidewalk, seeing the same dog, will say that your dog is moving because it has MOTION from your car

3 0
3 years ago
The equation E = mc2 relates energy and
mart [117]
The answer is D. mass  ...
6 0
3 years ago
A 75 kg bungee jumper leaps from a bridge. When he is 30 meters above the water, and moving at a speed of 20 m/s, the bungee cor
jasenka [17]

Answer:

k = 52.2 N / m

Explanation:

For this exercise we are going to use the conservation of mechanical energy.

Starting point. When it is 30 m high

        Em₀ = K + U = ½ m v² + m g h

Final point. Right when you hit the water

        Em_{f} = K_{e} = ½ k x²

in this case the distance the bungee is stretched is 30 m

        x = h

as they indicate that there are no losses, energy is conserved

        Em₀ = Em_{f}

       ½ m v² + m g h = ½ k h²

       k = \frac{m (v^{2} + 2 g h)}{h^{2} }

let's calculate

       k = \frac{75 \ ( 20^{2}  + 2 \ 9.8 \ 30)}{30^{2} }

       k = 52.2 N / m

3 0
3 years ago
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