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3 years ago

Sketch seven points. Then, connect the points to form a closed plane figure. What kind of polygon did you draw?

Mathematics

2 answers:

weqwewe [10]3 years ago

7 0

It’s a heptagon, which has seven points.

denis-greek [22]3 years ago

6 0

Answer:

A Polygon that has 7 points would have to be a heptagon.

Step-by-step explanation:

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What is the value of i^n if the remained of n/4 is 2<br> A. i<br> B. -i<br> C. -1<br> D. 1

Setler [38]

Answer:

Step-by-step explanation:

3 0

2 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago

HELP ASAP STEP BY STEP FIRST TO ANSWER IS BRAINLEIST!

irina [24]

卂几丂山乇尺

_____________________

7) 8hours

8) 10 pizzas

9) 13 packets

_______________________

EXPLANATION .:

_____(7)______________

Stacy's earning per hour babysitting

= 12$

Thus on Friday to earn 36$,

she would have worked 36/12 = 3 hours

On Saturday she earned 60$,

thus the time she worked = 60/12 = 5 hours

So the total time Stacy babysited on both days = 3+5 = 8hours

_______(8)__________________

Total ounces with Marco = 147

Ounces required for 1 pizza = 13

Ounced required for 1 breadstick = 2

Now when he has already made 3 breadsticks thus he would have used 3×2 = 6 ounces

So the remaining ounces = 147-6 = 141

Hence he can make 141/13 = 10.8 or 10 pizzas.

___________(10)_____________

Mr.Dundford gives 6 pencils to each student => for 30 students the pencils required would be 30×6 = 180

Now when he had already 24 pencils Thus the remaining = 180-24 = 156

Also there are 12 pencils in a packet

=> packets required = 156/12 = 13

___________________________

___________________

____________

_______

___

8 0

3 years ago

Read 2 more answers

Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4y

stealth61 [152]

First start by writing th equation y=mx+b then because we know the slope (m) is perpendicular to the other line we can find it. so it would be the negative reciprocal to -13 which is 1/13 then you can use the slope and the x and y point and sub them into the equation to find the b value
y=3 x=4 m=1/13
3=1/13*4+b then solve for b
3=4/13+b
3-4/13=b
2.69=b
the write out the equation
y=1/13x+2.69

4 0

3 years ago

Read 2 more answers

Samples of rejuvenated mitochondria are mutated(defective) in 1% ofcases. Suppose 15 samples are studied, and they can be consid

Bezzdna [24]

Answer:

A)0.86

B)0.99

C)6.047E-13

Step-by-step explanation:

Since p = 0.01 and q= 0.99

Number of event n = 15

Using binomial expansion

A) Probability (No samples are mutated) = 15C0 (p)^0 * (q)^15

= 1*(0.01)^0*(0.99)^15 = 0.86

B)Probability (At most one sample is mutated) = 15C0 * p^0 *q^15 + 15C1 * p^1 * q^14 = 1*(0.01)^0*(0.99)^15 + 15C1 * 0.01 * 0.99^14 = 0.86 + 15*0.01*0.8687 = 0.86 + 0.13 = 0.99

C) Probability (More than half the samples are mutated) = 15C8* 0.01^8 * 0.99^7 + 15C9* 0.01^9 * 0.99^6 +15C10* 0.01^10 *0.99^5 + 15C11 * 0.01^11 * 0.99^4 + 15C12 * 0.01^12 * 0.99^3 + 15C13 * 0.01^13 * 0.99^ 2 + 15C14 * 0.01^14 * 0.99^1 + 15C15 * 0.01^15 * 0.99^0

Probability (More than half the samples are mutated) = 6E-13 + 4.71E-15 + 2.86E-17 + 1.31E-19 + 4.41E-22 + 1.03E-24 + 1.49E-27 + 1E-30 = 6.047E-13

3 0

3 years ago