4 minutes and 30 seconds go into 2 hours 26 times
119
To solve this we are going to use the formula for speed:

where

is the speed

is the distance

is the time
Let

be the speed of the boat in the lake,

the speed of the boat in the river,

the time of the boat in the lake, and

the time of the boat in the river.
We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span>

We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span>

<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span>

But we know that

, so:

equation (1)
Speed of the boat traveling in the lake:

But we know that

, so:

equation (2)
Solving for

in equation (1):


equation (3)
Solving for

in equation (2):




equation (4)
Replacing equation (4) in equation (3):


Solving for

:






or

We can conclude that the speed of the boat traveling in the lake was either
6 km/hour or
5 km/hour.
Answer:
[A] use the complementary relationship between sine and cosine to rewrite sin(x + y) as cos(pi/2-(x+y)). apply the cosine sum identity. then simplify using sin(–y) = –sin(y) and cos(–y) = cos(y).
Step-by-step explanation:
i got it right
screw that other person l0l
note that sin(-x)=-sin(x) and cos(-x)=cos(x)
so sin(-y)=-sin(y) and cos(-y)=cos(y)
or something like that idfk
Answer:
It's false.
Step-by-step explanation:
Dont ask me! all i know is that no.4 is false and that I learned bar lines and negitives in 5th grade!!