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Firlakuza [10]
2 years ago
7

Bfksksbckdnxjmcbssoxonxnf

Mathematics
2 answers:
erastovalidia [21]2 years ago
7 0

Answer:

28

Step-by-step explanation:

have a wonderful day!!!!

Amanda [17]2 years ago
6 0

Answer:

The LCM of 4 and 7 is 28

Step-by-step explanation:

LCM is the lowest common multiple of two or more numbers.

To find it do that:

  • List the multiples of each number
  • Find the first common multiple of them, it will be the LCM

Let us find the lowest common multiple of 4 and 7

→ List the multiples of 4

∵ The multiples of 4 are, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, .......

→ List the multiples of 7

∵ The multiples of 7 are, 7, 14, 21, 28, 35, 42, 49, .........

→ Find the first common multiple of 4 and 7

∵ 28 is the first common multiple of 4 and 7

∴ The lowest common multiple of 4 and 7 is 28

∴ The LCM of 4 and 7 is 28

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Check all that apply. Sec θ is undefined for θ = ____. A. π. B. π/2. C. 0. D. 3π/2.
Zanzabum
Secant is a trigonometric function that is the reciprocal of the function cosine. This means that in a cartesian plane, the value of secant is equal to r / x. For the values to be undefined, x should be zero. The angles are π/2 and 3π/2. The answers are B and D. 
8 0
3 years ago
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Olga has 5 times as many dimes as nickels. if she has $3.30, how many of each coin does she have
Colt1911 [192]
She should have 
nickles: 6 . =30
dimes: 30 . = 300
             =330 .   or $3.30
6 0
3 years ago
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An NBA fan named Mark claims that there are more fouls called on his team 1 point
inn [45]

Answer:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

df = n-1=34-1=33

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

Step-by-step explanation:

Information provided

\bar X=12.2 represent the sample mean fould against

s=1.6 represent the sample standard deviation

n=34 sample size  

represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:  

Null hypothesis:\mu \leq 11.5  

Alternative hypothesis:\mu > 11.5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

P value

The degreed of freedom are given by:

df = n-1=34-1=33

Since is a one side test the p value would be:  

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

7 0
3 years ago
Anna went from home to school with the speed 3 km/hour. She ran back home with the speed 6 km/hour.Her sister Olga went to schoo
PIT_PIT [208]
Let:
v = Olga's speed
t = the time Anna spent going to school (3 km/hour)
t/2 = the time Anna spent running back home with speed of 6 km/hour
So, t + t/2 = 3t/2 is the total time
In the meantime distance = speed*time and the both made the same distance we can put it as:
3t + 6*(t/2) = (3t/2)*v
6t = (3/2)tv divide both sides by t 
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3 0
3 years ago
Micahdisu please help
skad [1K]

Answer:

1) A - 42°

2) 74°

3) B - 45°

4) B - 66°

Step-by-step explanation:

1) E = D+H

87 = 45 + H

H = 42°

2) 180 - 50 - D

D = 180 - 44 - 62 = 74°

3) F = 105

H = 180-105 = 75

I + H = C + E

I + 75 = 83 + 37

I = 45°

4) D = 180 - (E + F)

D = 180 - (30 + 57) = 93°

93 = A + 27

A = 66°

4 0
3 years ago
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