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Igoryamba
3 years ago
6

How does one do this? I’ve tried and still can’t get it please help

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

20

Step-by-step explanation:

An angle bisector cuts an angle into two equal parts.  So m∠ACE = m∠ECB.

m∠ACE = m∠ECB

2x − 15 = x + 5

x = 20

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Find the area of the triangle below.
d1i1m1o1n [39]

Answer:

   45.5

Step-by-step explanation:

Use pyth theorem to find the whole bottom side. Then sub 16 by 13. # is the small segmented area. The small segmented tri is 10.5 area. The big tri is 56. Sub 10.5 from 56 to get 45.5.

4 0
2 years ago
Find the distance between the points.<br><br> (9.7, -2.1), (-3.2, 8.1)
seropon [69]
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4 0
3 years ago
Graph: y - 10 = -2(z – 10)
ZanzabumX [31]
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3 years ago
You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,
Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

X = 96, \mu = 72, \sigma = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 72}{12}

Z = 2

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0
3 years ago
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mojhsa [17]

To find the answer, multiply 22 1/2 by 3.

22 1/2 x 3 = 67 1/2

This can round up to 68

The answer is C. 68 mph

If you have any further questions feel free to ask.

Hope this helps.

7 0
3 years ago
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