How does one do this? I’ve tried and still can’t get it please help

1 answer:

6 0

Answer:

Step-by-step explanation:

An angle bisector cuts an angle into two equal parts. So m∠ACE = m∠ECB.

m∠ACE = m∠ECB

2x − 15 = x + 5

x = 20

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Lunna [17]

The answer is 75 degrees I believe.

45 + 60 + x = 180

I’m pretty sure I’m correct but I’m so sorry if I’m wrong.

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olya-2409 [2.1K]

Answer for this question is -32

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scoundrel [369]

Choice A is the most reasonable estimate

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Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
After simplyfying the expressions we get finally : -12+8x-8y=0
now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16