Answer:
15 yd^2
Step-by-step explanation:
a= 1/2bh
a= 1/2(3)10
a= 1/2(30)
a= 15
Answer:
The answer to your question is:
Packages of pencils = 6
Packages of erasers = 5
Step-by-step explanation:
Data
Pencils = 10/package
Erasers = 12 / package
Process
Find the least common factor of 10 and 12
10 12 2
5 6 2
5 3 3
5 1 5
1
LCF = 2 x 2 x 3 x 5 = 60
Finally divide 60 by the number of pencils or erasers in each package
Packages of pencils = 60/10 = 6
Packages of erasers = 60/12 = 5
ANSWER

EXPLANATION
The given product is:

We expand using the distributive property to obtain:

Extract the perfect squares to get:

Expand further to get;

This simplifies to,

The decrease in the value of the toy is $9.25 if you subtract $ 0.75 from $10.00 then you get $9.25 so it's $9.25 cheaper
Step-by-step explanation:
Hey there!
Given sequences are; 2 , 13 , 24 , 35 , _ , _ .
Now,
Common difference (d) = 2nd term - 1st term. = 13-2 = 11
When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.
Now, let's find the nrh term of the sequence.
nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)
nth = 2+ (n-1) 11
= 2 + 11n - 11
= 11n - 9
Let's check if we have got nth term correct.
a1= 1*11 - 9 = 2
a2 = 2*11-9 = 13
a3 = 3*11 - 9 = 24
a4 = 4*11-9 = 35
So, we got our nth term.
Let's find remaining sequence.
a5= 5*11 - 9 = 46.
a6= 6*11 - 9 = 57.
Therefore, the remaining terms are : 46 and 57.
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>