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jeka94
3 years ago
7

If an organization does not develop programs in-house, then the development group of the information system (IS) department will

be staffed primarily by ________ who work with users, operations, and vendors to acquire and install licensed software and to set up the system components around that software.
A) Programmers and development personnel
B) PQA test engineers
C) Business and systems analysts
D) Technical writers
Business
2 answers:
Nitella [24]3 years ago
4 0

Answer:

C) Business and systems analysts

Explanation:

Business and systems analysts primarily work with users, operations, and vendors to acquire and install licensed software and to set up the system components around that software.

They can be found in the information system (IS) department of an organization.

klio [65]3 years ago
4 0

Answer: Business and systems analysts

Explanation:

A business and systems analyst is someone who works with the computer technology that is required by an organization or business. A business and systems analysts determine the type of technological upgrades and installations that will improve efficiency and effectiveness in the workplace.

The roles of a business and systems analyst include designing new computer programs by

constructing workflow charts, analyzing requirements and studying system capabilities.

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If a company abandons a segment of its operation, the loss would be reported on the a.income statement immediately after cost of
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Answer:

d.income statement immediately after income from continuing operations.

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As the firm should firm indicate the resulf the going business the discontinued operation should be disclosure separately from it. Thus, once complete the disclosure of the continued operation the firm should post the loss on this discontinued operation

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3 years ago
Match the following terms to their definition: 1. expected value 2. liquidity 3. fixed assets 4. point of sales terminals 5. sel
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1.A representative quantity from a probability distribution arrived at by multiplying each outcome times the associated probability and summing up the products.

2.The relative convertibility of short-term assets to cash.

3.Assets that are assumed to be long term in nature.

4. Computer terminals in retail stores that may be used for inventory control or other purposes.

5. Assets that are converted to cash within the normal operating cycle of the firm.

6.Financing provided by sellers or suppliers in the normal course of business.

7.Equal monthly production used to smooth out production schedules and employ manpower and equipment more efficiently.

Explanation:

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3 years ago
Sixty-second Avenue Inc. expects to earn $5,700,000 this year. The company currently has 790,000 shares outstanding, and the sha
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Answer:

The company's expected market price per share After the repurchase would $23.68

Explanation:

In order to calculate the company's expected market price per share After the repurchase we would have to calculate first the Price-to-earnings ratio ( P/E ratio ) as follows:

Price-to-earnings ratio ( P/E ratio )= Market price per share / Earnings per share

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7 0
3 years ago
A new highway is to be constructed.
baherus [9]

Answer:

Desing B

<u><em>Total Present worth</em></u>     $  502.485,35‬

<u><em>Annual worth:</em></u>              $    49,722.003

Option 2:

<u><em>Total Present worth</em></u>     $  666.441,33‬

<u><em>Annual worth:</em></u>              $   53,845.798

Explanation:

<h2>Desing A</h2>

$85 x 5280     =   448,800

$4 x 3 x 5280  =     63,360

$8000 x 4        = <u>    32,000  </u>

total cost:                544,160‬

Annual cost:

11,800 + 300 = 12,100

PV of the annual maintenance:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 12,100.00

time 16

rate 0.06

12100 \times \frac{1-(1+0.06)^{-16} }{0.06} = PV\\

PV $122,281.3328

<u><em>Present worth:</em></u>

total cost to construct  544,160‬ + maintenance $122,281.33 = 666.441,33

<u><em>Annual worth:</em></u>

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\

PV 544,160

time 16

rate 0.06

544160 \div \frac{1-(1+0.06)^{-16} }{0.06} = C\\

C  $ 53,845.798

<h2>Desing B</h2>

a mile is equivalent to 5,280 foot

paviment $40 x 5,280 = $ 211,200

sood ditched 2 per foot x 5,280 foot per mile x $1.40 = $ 12,038.4

pipe culvert 2,200 x 2 = 4,400

Total value to construct: 227.638,4‬

PV of maintenance:

replacement 2,400 x 2 = 4,800 (in 8 years)

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $4,800.0000

time  8.00

rate  0.06000

\frac{4800}{(1 + 0.06)^{8} } = PV  

PV   3,011.5794

maintenance $2,900

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ditch 1.45 x 5,280 x 2 = $ 15,312

Total yearly cost: 18.672‬

PV of this annuity over 16 years:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 18,672.00

time 16

rate 0.06

18672 \times \frac{1-(1+0.06)^{-16} }{0.06} = PV\\

PV $188,697.2765

PV of the replacement bituminous concrete

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $211,200.0000

time  16.00

rate  0.06000

\frac{211200}{(1 + 0.06)^{16} } = PV  

PV   83,138.0951

<u><em>Present worth:</em></u>

Total value to construct: $  227.638,4‬ +

yearly cost PB                 $  188,697.28 +

concrete replacement    $ 83,138.0951

culvert replacement:       $<u>   3,011.58      </u>

Total Present worth        502.485,35‬

<u><em>Annual worth:</em></u>

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\

502485.35 \div \frac{1-(1+0.06)^{-16} }{0.06} = C\\

C  $ 49,722.003

<em><u /></em>

6 0
2 years ago
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