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Andrei [34K]
3 years ago
6

In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of

the wood pile was used up at the end of February?
Mathematics
1 answer:
arsen [322]3 years ago
6 0
2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used
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0, 1, 2

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Combine like terms;

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givi [52]

-4x - 5y = 7

3x + 5y = -14

You can add these two equations together straightaway since the y-terms have opposite coefficients.

-4x - 5y = 7

3x + 5y = -14

+___________

-x - 0 = -7

-x = -7

x = 7

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3x + 5y = -14

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Finally, check work by substituting both x- and y-values into both original equations.

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3 years ago
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Marianna [84]

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8 0
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