Question

A mixture of alcohol and water contains a total of 60 oz of liquid there are 12 oz of pure alcohol in the mixture was a percentage of the mixture is water what is the percent alcohol

Answer 1

Answer:

The mixture contains 80% water and 20% alcohol.

Step-by-step explanation:

Given:

Total Amount of mixture = 60 oz

Amount of alcohol in the mixture = 12 oz

We need to find the percentage of water and percentage of alcohol in the mixture.

Solution:

First we will find the amount of water in mixture.

Now we know that;

Total Amount of mixture is equal to sum of Amount of alcohol in the mixture and amount of water in mixture.

so we can say that;

amount of water in mixture = Total Amount of mixture - Amount of alcohol in the mixture

amount of water in mixture = $60-12 =48\ oz$

Now we will find the Percentage amount of water.

Percentage amount of water can be calculated by dividing amount of water in mixture by Total Amount of mixture and then multiplying by 100.

framing in equation form we get;

Percentage amount of water = $\frac{48}{60}\times 100 = 80\%$

Percentage amount of alcohol = $100\%-80\%=20\%$

Hence The mixture contains 80% water and 20% alcohol.