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Oduvanchick [21]
3 years ago
7

exactly 5.00 L of air at -50.0 °C is warmed to 100.0 °C. What is the new volume if the pressure remains constant?

Chemistry
1 answer:
ollegr [7]3 years ago
3 0

Answer:

V₂ = 8.36 L

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = -50.0°C (-50 + 273 = 223 k)

Final temperature = 100°C (100+273 = 373 k)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 5.00 L × 373 K / 223 K

V₂ = 1865 L.K / 223 K

V₂ = 8.36 L

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a- 0.10 mol

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The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
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In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

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The mass number is the sum of the protons and the neutrons

In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72

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