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irakobra [83]
2 years ago
6

Please help! I will give 100pts and brainliest!!!

Chemistry
2 answers:
kirza4 [7]2 years ago
8 0

Answer:

What do you need help with?

Explanation:

Ainat [17]2 years ago
3 0

Answer:

there is no question...please attache it...

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1. Given the specific heat of lead is 0.129 J/g.C and that it takes 93.4J of energy to
zheka24 [161]

Answer: 40 grams

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = 93.4J

M = ?

C = 0.129 J/g.C

Φ = 40.4°C - 22.3°C = 18.1°C

Then, Q = MCΦ

Make Mass, M the subject formula

M = Q/CΦ

M = (93.4J) / (0.129 J/g.C x 18.1°C)

M = 93.4J / 2.33J/g

M = 40 g

Thus, the mass of the lead is 40 grams

8 0
3 years ago
State what method you would use the separate water from a potassium iodide solution​
tia_tia [17]

Answer:

<u>distillation</u> is the method used to separate water from a potassium iodine solution

Explanation:

hope it helps !!

4 0
3 years ago
Read 2 more answers
What are the ion concentrations in a 0.12 M solution of AlCl3? A) 0.12 M Al3+ ions and 0.040 M Cl- ions B) none of the answers C
KIM [24]

Answer:

D

Explanation:

To answer this question, we will need to write the dissociation equation of aluminum trichloride.

AlCl3 ——-> Al3+ + 3Cl-

It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.

From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same

5 0
3 years ago
A solution of NaF is added dropwise to a solution that is 0.0144 M in Ba2+. When the concentration of F- exceeds ________ M, BaF
BARSIC [14]

Answer:

When the concentration of F- exceeds 0.0109 M, BaF2 will precipitate.

Explanation:

Ba²⁺(aq) + 2 F⁻(aq) <----> BaF₂(s)

When BaF₂ precipitates, the Ksp relation is given by

Ksp = [Ba²⁺] [F⁻]²

[Ba²⁺] = 0.0144 M

[F⁻] = ?

Ksp = (1.7 × 10⁻⁶)

1.7 × 10⁻⁶ = (0.0144) [F⁻]²

[F⁻]² = (1.7 × 10⁻⁶)/0.0144 = 0.0001180555

[F⁻] = √0.0001180555 = 0.01086 M = 0.0109 M

Hope this Helps!!!

7 0
3 years ago
What is the complete word equation for incomplete combustion for methane
Arada [10]
Incomplete combustion is formed like: hydrocarbon + oxygen-> carbon + carbon monoxide + water!
8 0
2 years ago
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