Why aren't noble gases included in the trend for electronegativity?

2 answers:

8 0

They are unreactive becuase noble gases have 8 valence electrons..therefore they are stable. An atom can only contain 8 valence electrons

Andrew [12]3 years ago

5 0

Noble gases are almost completely unreactive because they have a complete number of electrons on their valence electron level. So noble gases HAVE NO charge, thus they are not included on the electronegativity trend.

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Which equation represents a neutralization reaction?

netineya [11]

Answer:

a. LiOH(aq) + HBr(aq) -> LiBr(aq) + H2O(l)

Explanation:

This is a neutralization reaction (acid-base reaction) LiOH is a base and HBr is an acid.

7 0

3 years ago

For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →

Vinvika [58]

Answer : The oxidizing element is N and reducing element is O.

$KNO_{3}$ is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

$KNO_{3}$ act as an oxidizing agent.

The oxidation number of N in $KNO_{3}$ is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in $KNO_{2}$ is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number reduced this means $KNO_{3}$ itself get reduced to $KNO_{2}$ and it can act as an oxidizing agent.

$KNO_{3}$ act as a reducing agent.

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

The oxidation number of O in $KNO_{3}$ is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in $O_{2}$ is Zero (o).