Answer:
- <u>Freezing point: - 1.83ºC</u>
- <u>Boiling point: 100.50ºC</u>
Explanation:
The <em>freezing point</em> and<em> boiling point</em> of solvents, when a solute is added, will change accordingly to the concentration of the solute particles.
The freezing point will decrease and the boiling point will increase. These are two colligative properties.
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<u>Find attached the file with the whole answer, as the site is not uploading the answer in here.</u>
Explanation:
A clastic sedimentary rock is a rock that is formed from pre-existing rock materials and minerals. This materials have been transported to their new positions by the agents of denudation.
- Clastic sedimentary rocks are made up of rock fragments predominantly.
- The matrix is usually remnants of other rocks.
- A cementing material can form between clasts and holds them in place. Cements are usually iron oxides, calcite e.t.c.
- These rock types are usually formed from mechanincal weathering of rocks
- Mechanical weathering breaks down rocks into chunks.
- Examples are breccia, conglomerates, e.t.c.
Learn more:
Sedimentary rocks brainly.com/question/2740663
#learnwithBrainly
Answer:
3. Which side of the chain should you count from when naming organic compounds?
C) Side that will give you the longest Carbon chain
4. What is the pH of a solution with a pOH of 10?
C) 4
pH + pOH = 14
pH + 10 = 14
pH = 14 - 10
pH = 4
<u>-TheUnknownScientist</u>
Assuming its at r. t.p and pressure
no. of moles = 96/24=4moles
altho some books will say that its 23.7dm3/mole but that doesnt really matter because its the process that matters
The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.
Isotope mass amu Relative abundance
1 77.9 14.4
2 81.9 14.3
3 85.9 71.3
Express your answer to three significant figures and include the appropriate units.
Answer: 84.2 amu
Explanation:
Mass of isotope 1 = 77.9
% abundance of isotope 1 = 14.4% = 
Mass of isotope 2 = 81.9
% abundance of isotope 2 = 14.3% = 
Mass of isotope 3 = 85.9
% abundance of isotope 2 = 71.3% = 
Formula used for average atomic mass of an element :
![A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2877.9%5Ctimes%200.144%29%2B%2881.9%5Ctimes%200.143%29%2B%2885.9%5Ctimes%200.713%29%5D)
Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu
