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AnnZ [28]
3 years ago
14

Can someone please help me?​

Mathematics
1 answer:
uysha [10]3 years ago
5 0

Answer:

15.5 seconds.

Step-by-step explanation:

From the time the driver activated the brakes until he stopped, he travelled 76 - 14 = 62 meters.

During this time the car slowed  down from 8 m/s to 0 m/s.

Assuming the deceleration was constant during this time we can apply one of the equations of motion for constant  acceleration:

s = (u + v)t / 2   where u = initial velocity, v = final velocity, s = distance and t = the time, so:-

62 = (8 + 0)t/ 2

62 = 8t/2

4t = 62

t = 15.5 seconds.

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Twice the difference of a number and 2 is at most -27
igor_vitrenko [27]
<h2>Explanation:</h2><h2 />

When we say "a is at most b" we mean that "a is less than or equal to b" or "a is not greater than b". So let's solve this problem as follows:

Step 1. Twice the difference of a number and 2

Let's call that unknown number as n. Then, twice the difference of a number and 2 is:

2(n-2)

Step 2. Twice the difference of a number and 2 is at most -27

2(n-2)\leq -27

_________________________________________

So the mathematical form of the statement <em>twice the difference of a number and 2 is at most -27 </em>is:

\boxed{2(n-2)\leq -27}

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3 years ago
HELP PLEASE !!!!! A person is on the top of a 60 m tall building. They throw a coin up into the air with a velocity of 15 m/s. H
Anon25 [30]

Answer:

-24.8 m/s

Step-by-step explanation:

Given:

y₀ = 60 m

y = 40 m

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a = -9.8 m/s²

Find: v

There are three constant acceleration equations we can use:

y = y₀ + v₀ t + ½ at²

v = at + v₀

v² = v₀² + 2a(y − y₀)

We aren't given the time, so we need to use the third equation, which is independent of time:

v² = v₀² + 2a(y − y₀)

Plug in the values:

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Since the coin is on the way down, the velocity is negative.  So v = -24.8 m/s.

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