Answer:
15.5 seconds.
Step-by-step explanation:
From the time the driver activated the brakes until he stopped, he travelled 76 - 14 = 62 meters.
During this time the car slowed down from 8 m/s to 0 m/s.
Assuming the deceleration was constant during this time we can apply one of the equations of motion for constant acceleration:
s = (u + v)t / 2 where u = initial velocity, v = final velocity, s = distance and t = the time, so:-
62 = (8 + 0)t/ 2
62 = 8t/2
4t = 62
t = 15.5 seconds.
64/672/882(986)*866772
100,000
