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Andrei [34K]
3 years ago
10

Write the monomial in standard form. name it's coefficient and identify its degree.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

Standard\ Form = {3n^2} m^{-2}

Step-by-step explanation:

Given

\frac{2}{3m^2n} * 4.5n^3

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

\frac{2}{3m^2n} * 4.5n^3

Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}

Split the numerator and the denominator

Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}

Multiply Like terms

Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}

Divide 9 by 3 to give 3

Standard\ Form = \frac{3 * n^3}{m^2 * n}

Divide n³ by n to n²

Standard\ Form = \frac{3 * n^2}{m^2 }

Split fraction

Standard\ Form = {3 * n^2} * \frac{1}{m^2 }

From laws of indices;

\frac{1}{a^n} = a^{-n}

Standard\ Form = {3 * n^2} * \frac{1}{m^2 } becomes

Standard\ Form = {3 * n^2} * m^{-2}

Multiply all together

Standard\ Form = {3n^2} m^{-2}

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