Question

In ΔBCD, \overline{BD} BD is extended through point D to point E, \text{m}\angle CDE = (9x-12)^{\circ}m∠CDE=(9x−12) ∘ , \text{m}\angle BCD = (2x+3)^{\circ}m∠BCD=(2x+3) ∘ , and \text{m}\angle DBC = (3x+5)^{\circ}m∠DBC=(3x+5) ∘ . Find \text{m}\angle BCD.M∠BCD.

Answer 1

Answer:

Angle BCD is 13 degrees

Step-by-step explanation:

Here, we want to find the measure of angle BCD

To get this, we need an appropriate diagram. The diagram can be seen in the attachment.

To find the value of BCD, we can use an important triangle theorem.

This is that the sum of opposite interior angles of a triangle equals the exterior angle.

Thus, we have that;

BCD + DBC = CDE

hence;

3x + 5 + 2x + 3 = 9x-12

5x + 8 = 9x -12

9x-5x = 8 + 12

4x = 20

x = 20/4

x = 5

So the measure of BCD will be 2(5) + 3 = 10 + 3 = 13